To solve the Tower of Hanoi problem using JavaScript, you can use recursion or a loop approach to move the n disks from one peg to another. Here's an example using recursion:```javascriptfunction towerOfHanoi(n, source, auxillary, target) { // Base case: moving n - 1 disks from source to auxiliary if (n === 1) { console.log("Move disk 1 from peg " + source + " to peg " + target); return; } // Recursive case: moving n - 1 disks from source to auxiliary, then moving the nth disk from source to target towerOfHanoi(n - 1, source, target, auxillary); // Move the nth disk from source to target console.log("Move disk " + n + " from peg " + source + " to peg " + target); // Recursively move the remaining n-1 disks from auxiliary to target towerOfHanoi(n - 1, auxillary, target, source);}// Example usagetowerOfHanoi(3, 'A', 'B', 'C');```In this implementation, the `towerOfHanoi` function takes four parameters:1. `n`: The number of disks to be moved.2. `source`: The starting peg from which the disks start.3. `auxillary`: The temporary peg where the smaller disks are placed while moving the larger disks to their final destination.4. `target`: The destination peg where the disks should be placed.The function first checks for the base case, which is when there is only one disk to be moved (case `n = 1`). In this case, it simply prints out the move instruction for moving the disk from the source peg to the target peg.If `n > 1`, the function makes a recursive call to itself with `n - 1` disks as the source, `target` as the auxiliary, and `source` as the current target peg. This step moves the `(n - 1)` disks from the source peg to the auxiliary peg.After making the recursive call, it moves the `n`th disk from the source peg to the target peg. Then, it recursively calls itself with `n - 1` disks again on the auxiliary peg, but this time, it places the `n`th disk on top of the already moved disks on the target peg.Finally, it recursively moves the remaining `n - 1` disks from the auxiliary peg to the target peg, by calling itself with the auxiliary peg as the source, the target peg as the auxiliary, and the source peg as the current target peg.This process continues until all `n - 1` disks have been moved from the source peg to the target peg, and all disks are placed on the correct pegs.Note that this implementation assumes that the input value `n` represents the total number of disks rather than the actual disk numbers being moved. If the input value `n` could be different from the actual values, you would need to modify the function accordingly to accommodate for the appropriate `n` value. |